MHB Factor $x^2-24x-17280$ Quickly & Effectively

  • Thread starter Thread starter bergausstein
  • Start date Start date
AI Thread Summary
The quadratic expression $x^2-24x-17280$ can be factored as $(x-144)(x+120)$. To find the factors efficiently, the prime factorization of 17280 is utilized, which is $2^7 \cdot 3^3 \cdot 5$. The goal is to identify two factors that sum to -24, leading to the close values of 120 and 144. This method minimizes trial and error by focusing on the prime factors. The discussion highlights a systematic approach to factoring quadratics effectively.
bergausstein
Messages
191
Reaction score
0
help factor this out using a faster and effective way.

$x^2-24x-17280$

I know that the factored form is $(x-144)(x+120)$

when I solved this I'm having a hard time finding a product of two numbers that will give me the middle term. can you give some fast way to determine that? with much less use of repetitious trial and error. thanks!
 
Mathematics news on Phys.org
I would first look at the prime factorization:

$$17280=2^7\cdot3^3\cdot5$$

Now, we want to find two factors whose sum is $-24$, so we know the two factors will need to be close in value. So, we could try:

$$17280=\left(2^3\cdot3\cdot5\right)\left(2^3\cdot3\cdot6\right)=120\cdot144$$

And this turns out to be the factors we need. :D
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...
Thread 'Video on imaginary numbers and some queries'
Hi, I was watching the following video. I found some points confusing. Could you please help me to understand the gaps? Thanks, in advance! Question 1: Around 4:22, the video says the following. So for those mathematicians, negative numbers didn't exist. You could subtract, that is find the difference between two positive quantities, but you couldn't have a negative answer or negative coefficients. Mathematicians were so averse to negative numbers that there was no single quadratic...
Thread 'Unit Circle Double Angle Derivations'
Here I made a terrible mistake of assuming this to be an equilateral triangle and set 2sinx=1 => x=pi/6. Although this did derive the double angle formulas it also led into a terrible mess trying to find all the combinations of sides. I must have been tired and just assumed 6x=180 and 2sinx=1. By that time, I was so mindset that I nearly scolded a person for even saying 90-x. I wonder if this is a case of biased observation that seeks to dis credit me like Jesus of Nazareth since in reality...

Similar threads

Replies
1
Views
1K
Replies
2
Views
1K
Replies
5
Views
2K
Replies
4
Views
2K
Replies
15
Views
4K
Replies
2
Views
2K
Replies
12
Views
6K
Replies
3
Views
1K
Back
Top