Factoring a Sum of Cubes: How to Factor 8x^6+64?

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tmlfan_179027
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How would you factor 8x^6+64? My text states that the answer is 8(x^2+2)(x^4-2x^2+4). How would you get to that?
 
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Factoring out the 8 is easy.

Once you have that, it's clear that you have a sum of cubes: a^3 + b^3 = (a + b)(a^2 - ab + b^2)