Factoring Fractions: Simplifying Equations with Cancellation

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SUMMARY

The discussion focuses on simplifying the expression \(\pi a^2h - \frac{2}{3}\pi a^3\) through factoring and cancellation techniques. The solution demonstrates that the expression can be factored as \(\frac{\pi a^2}{3}(3h - 2a)\) by obtaining a common denominator and applying algebraic laws. Key methods highlighted include multiplying and dividing by the same number and the importance of understanding the laws of fractions for simplification. Participants emphasize the need for practice to master these techniques.

PREREQUISITES
  • Understanding of basic algebraic operations
  • Familiarity with fraction manipulation
  • Knowledge of factoring techniques
  • Ability to apply the laws of fractions
NEXT STEPS
  • Study the laws of fractions and their applications in algebra
  • Practice factoring polynomials and rational expressions
  • Learn about common denominators and their significance in simplification
  • Explore advanced algebra techniques, such as the quadratic formula for comparison
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Students, educators, and anyone looking to enhance their skills in algebraic simplification and fraction manipulation.

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Hi , So far I am stuck in this math problem and

View attachment 5779 MINUS (-) View attachment 5780

Subtract the first sum with pie from the second sum and you should factor it such that the a similar out come in the below given image.


Can anyone subtract and factor this for me such that View attachment 5778

and can you explain me how you did this in a little descriptive manner

Many thanks
 

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Get a common denominator and then factor.
 
I'm sorry would you be kind enough to demonstrate please!
 
$$\pi a^2h-\frac23\pi a^3=\frac{\pi a^2}{3}\cdot3h-\frac{\pi a^2}{3}{2a}=\frac{\pi a^2}{3}(3h-2a).$$
 
Thank you , can you explain a little bit on how did you solved this problem.

Many Thanks
 
mathlearn said:
can you explain a little bit on how did you solved this problem.
If you are asking how one comes up with the exact sequence of expressions $E_1,\dots,E_n$ such that $\pi a^2h-\dfrac23\pi a^3=E_1\dots=E_n=\dfrac{\pi a^2}{3}(3h-2a)$, it becomes quite obvious after some practice. If you are asking about a specific equality or transition that you don't understand in my solution, please say which one.
 
Where did /3 come from in the second step & can you explain a little step by step in doing this
 
I am using the following laws:
\begin{align}
&(1)\quad x\cdot1=x\\
&(2)\quad\dfrac{3}{3}=1\\
&(3)\quad x\dfrac{y}{z}=\dfrac{xy}{z}\\
&(4)\quad xy=yx\\
&(5)\quad (xy)z=x(yz).
\end{align}

So
\[
\pi a^2h\overset{(1)}{=}\pi a^2h\cdot1\overset{(2)}{=}\pi a^2h\cdot\dfrac33\overset{(3)}{=}\frac{\pi a^2h\cdot3}{3}\overset{(4,5)}{=}\frac{(\pi a^2)(3h)}{3}
\overset{(3)}{=}\frac{\pi a^2h}{3}\cdot 3h.
\]
 
Many thanks,
Can I know the name of the method you used to solve this
for example like quadratic equations or so
 
  • #10
As I said, this is much easier than the quadratic formula and becomes obvious after some practice. The transformations used here can be called "multiplying and dividing by the same number" or "cancellation" (3 in the numerator cancels with 3 in the denominator).

It may be good to get a cheat sheet of laws of fractions, such as this one.
 

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