MHB Factoring Fractions: Simplifying Equations with Cancellation

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The discussion focuses on simplifying the expression πa²h - (2/3)πa³ through factoring and cancellation. The solution provided demonstrates how to achieve a common denominator and factor the expression to arrive at (πa²/3)(3h - 2a). Participants emphasize the importance of understanding each step in the process, particularly how to manipulate fractions and apply basic algebraic laws. The method used is described as "multiplying and dividing by the same number" or "cancellation," which simplifies the calculations. Overall, the conversation highlights the need for practice to master these techniques in factoring fractions.
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Hi , So far I am stuck in this math problem and

View attachment 5779 MINUS (-) View attachment 5780

Subtract the first sum with pie from the second sum and you should factor it such that the a similar out come in the below given image.


Can anyone subtract and factor this for me such that View attachment 5778

and can you explain me how you did this in a little descriptive manner

Many thanks
 

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Get a common denominator and then factor.
 
I'm sorry would you be kind enough to demonstrate please!
 
$$\pi a^2h-\frac23\pi a^3=\frac{\pi a^2}{3}\cdot3h-\frac{\pi a^2}{3}{2a}=\frac{\pi a^2}{3}(3h-2a).$$
 
Thank you , can you explain a little bit on how did you solved this problem.

Many Thanks
 
mathlearn said:
can you explain a little bit on how did you solved this problem.
If you are asking how one comes up with the exact sequence of expressions $E_1,\dots,E_n$ such that $\pi a^2h-\dfrac23\pi a^3=E_1\dots=E_n=\dfrac{\pi a^2}{3}(3h-2a)$, it becomes quite obvious after some practice. If you are asking about a specific equality or transition that you don't understand in my solution, please say which one.
 
Where did /3 come from in the second step & can you explain a little step by step in doing this
 
I am using the following laws:
\begin{align}
&(1)\quad x\cdot1=x\\
&(2)\quad\dfrac{3}{3}=1\\
&(3)\quad x\dfrac{y}{z}=\dfrac{xy}{z}\\
&(4)\quad xy=yx\\
&(5)\quad (xy)z=x(yz).
\end{align}

So
\[
\pi a^2h\overset{(1)}{=}\pi a^2h\cdot1\overset{(2)}{=}\pi a^2h\cdot\dfrac33\overset{(3)}{=}\frac{\pi a^2h\cdot3}{3}\overset{(4,5)}{=}\frac{(\pi a^2)(3h)}{3}
\overset{(3)}{=}\frac{\pi a^2h}{3}\cdot 3h.
\]
 
Many thanks,
Can I know the name of the method you used to solve this
for example like quadratic equations or so
 
  • #10
As I said, this is much easier than the quadratic formula and becomes obvious after some practice. The transformations used here can be called "multiplying and dividing by the same number" or "cancellation" (3 in the numerator cancels with 3 in the denominator).

It may be good to get a cheat sheet of laws of fractions, such as this one.
 

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