Factoring (x^n-a^n) with (x^2-a^2): Is it Possible?

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SUMMARY

Factoring the expression (x^n - a^n) with (x^2 - a^2) as one of its factors is conditionally possible. Specifically, (x^2 - a^2) can be expressed as (x - a)(x + a), which divides (x^n - a^n) under certain conditions related to the value of n. The discussion confirms that while (x - a) always divides (x^n - a^n), the divisibility of (x + a) depends on the specific circumstances of n.

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Homework Statement


I would like to factor (x^n-a^n) such that (x^2-a^2) is one of the factors. Is this possible?


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The Attempt at a Solution


I tried to get this with a kind of reverse polynomial long division, but couldn't do it.
 
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This factoring is possible for some cases of n. It is not true in general. (x^2-a^2) is equal to (x-a)(x+a). It certainly is the case that (x-a) divides (x^n-a^n). What is the quotient? Under what circumstances does (x+a) divide this quotient?
 

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