Hello there,(adsbygoogle = window.adsbygoogle || []).push({});

I'm quite weak in factorising functions,especially those with indices.

I would appreciate any link on these kind of factorisation or even some tutoring on it.

this is a question I'm stuck in.

y=(2x+3)(4x-3)^1/2, show dy/dx can be written in the form kx/(4x-3)^1/2

my solution:

dy/dx =v(du/dx) + u(dv/dx)

where u=2x+3

du/dx=2

v=(4x-3)^1/2

dv/dx= -2(4x-3)^-1/2

then, dy/dx=[(4x-3)^1/2 ]2 -(-2)(2x+3)[(4x-3)^-1/2]

= 2{(4x-3)^1/2 - (2x+3)(4x-3)^-1/2}

= . . . .

(stumped!)

I am not sure what to do after that

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Factorising a differntiated equation

**Physics Forums | Science Articles, Homework Help, Discussion**