Factorization and Simplifying.

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Homework Help Overview

The discussion revolves around simplifying the expression (x^3 + 3x^2 + 3x + 1)/(x^4 + x^3 + x + 1) through factorization, focusing on polynomial expressions with exponents higher than x^2.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the binomial expansion and synthetic division as potential methods for factorization. There are attempts to identify common factors, particularly noting that x = -1 results in both the numerator and denominator equaling zero, suggesting (x + 1) as a common factor. Some participants express uncertainty about how to initiate the factorization process.

Discussion Status

Several participants are exploring different methods of factorization and expressing their challenges in starting the process. Guidance has been offered regarding the use of synthetic division and the binomial expansion, but there is no explicit consensus on the next steps or a clear resolution yet.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the amount of direct assistance they can provide. There is an emphasis on understanding the factorization of higher-degree polynomials.

AstrophysicsX
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Homework Statement


Use Factorization to simplify the given expression.


Homework Equations


(x^3 + 3x^2 + 3x +1)/(x^4 + x^3 + x + 1)


The Attempt at a Solution


I can't get to the first step. I forgot how to factor exponents higher than x^2.
 
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Think about the binomial expansion of (a+b)3. Also you can check for roots using synthetic division. And remember a root x = r corresponds to a factor of x-r.
 
Theorem of the factor.

You can probably simplify the upper and the lower part, maybe even cancel out some stuff...
 
But how to do that is the problem.
 
AstrophysicsX said:
But how to do that is the problem.

If x=(-1) then the numerator and denominator are both 0. That means (x-(-1))=(x+1) is a common factor of the numerator and denominator. Now start factoring it out.
 
AstrophysicsX said:
(x^3 + 3x^2 + 3x +1)/(x^4 + x^3 + x + 1)

I can't get to the first step. I forgot how to factor exponents higher than x^2.

As others have pointed out, x=-1 is a "solution" to the numerator (equaling zero). So this tells you that (x+1) is a factor of the numerator. So what is the other factor?

If you don't like doing division, you can solve by doing multiplication. To start with, let's look at just the numerator:

x3 + 3x2 + 3x + 1 = (x+1)(x2 + Mx + C)

Multiply the right hand side to remove the brackets, and equate the coefficients on each side to determine the values of the unknowns M and C.
 

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