Factorize the following expression

  • Thread starter Thread starter abrowaqas
  • Start date Start date
  • Tags Tags
    Expression
Click For Summary

Homework Help Overview

The problem involves factorizing a cubic expression given by the equation p^3 - (x^2 + xy + y^2)p + xy^2 + x^2y = 0. The original poster (OP) is seeking assistance in understanding how to arrive at the provided factorization.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Some participants question the OP's understanding of the problem and seek clarification on what specific help is needed. Others suggest using known formulas for factoring cubic equations and discuss various techniques, including Cardano's method.

Discussion Status

The discussion is ongoing, with participants offering different perspectives on how to approach the factorization. Some guidance has been provided regarding techniques for factoring cubic expressions, but there is no explicit consensus on a single method or solution yet.

Contextual Notes

Participants note that the absence of a quadratic term in the equation may simplify the factorization process. There is also mention of adding and subtracting terms to facilitate factoring, indicating that the OP may have constraints or specific methods in mind.

abrowaqas
Messages
113
Reaction score
0

Homework Statement



Expression is
p^3-(x^2+xy+y^2)p+xy^2+x^2y=0 where ^ shows power

Homework Equations




The Attempt at a Solution


the solution is
(p-x)(p-y)(p+x+y)=0
 
Physics news on Phys.org
So, what's the question? I see an expression, told to factorize, and I see the solution. What's your question?
 
The OP would like to factor the expression on the left side of the equation, and is showing the solution shown in the book, but doesn't know how to get the factorization that is shown.

I believe the best way to crack this one is to use a known formula for factoring a cubic. Here's a discussion of several techniques - http://en.wikipedia.org/wiki/Cubic_equation. See the section titled "Cardano's method" on the linked-to page.

Factoring cubic equations is a lot more complicated than factoring quadratics, but the saving grace here is that there is no quadratic (p2) term in your equation, which should make the work a little easier.
 
Try adding and subtracting pxy to what's inside the parentheses to get

[tex]\begin{align*}<br /> 0 &= p^3-(x^2+xy+y^2+xy-xy)p+xy^2+x^2y \\<br /> &=p^3-(x^2+2xy+y^2)p + pxy + xy^2+x^2y \\<br /> &=p^3-(x+y)^2p+pxy+xy^2+x^2y<br /> \end{align*}[/tex]

Then pull common factors out of the first two terms and the last two terms. That should get you started.
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
3
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
7
Views
2K
Replies
10
Views
3K