Figure Eight Trajectories for Spacecraft: Potential Energy Calculation

  • Thread starter Thread starter dvvz2006
  • Start date Start date
Click For Summary
SUMMARY

The discussion focuses on calculating potential energy for spacecraft following figure-eight trajectories between Earth and the Moon. The potential energy formula combines the gravitational potentials of both celestial bodies, expressed as -GM/r^2 for Earth and -Gm/|r^2 + R^2| for the Moon. To find the position where potential energy is maximized, participants are instructed to set the derivative of the combined potential energy equation to zero. Finally, the potential energy at this maximum position is to be calculated as a fraction of the energy when the spacecraft is stationary at the Earth's surface.

PREREQUISITES
  • Understanding of gravitational potential energy equations
  • Familiarity with calculus, specifically derivatives
  • Knowledge of celestial mechanics and spacecraft trajectories
  • Basic physics concepts related to mass and gravitational forces
NEXT STEPS
  • Study gravitational potential energy calculations in multi-body systems
  • Learn about calculus applications in physics, particularly optimization techniques
  • Research spacecraft trajectory planning and dynamics
  • Explore the implications of potential energy in orbital mechanics
USEFUL FOR

Aerospace engineers, physicists, and students studying orbital mechanics or spacecraft trajectory optimization will benefit from this discussion.

dvvz2006
Messages
3
Reaction score
0
Hi, I was wondering if someone could help with the following problem. I am having trouble setting up the equation and a) and by looking at b and c, am unsure how to do those as well. The problem is as follows:

Figure eight trajectories are used to send spacecraft form the Earth to the Moon. Moving along these trajectories, the spacecraft remain close to the line connecting Earth and Moon. Along this line, the potential energy is lower than elsewhere in space. Assume that Earth and Moon are stationary and that a spacecraft has a mass of 1000kg. '

a) Give the formula of that combines the potential energies of Earth and Moon in a coordinate system in which the centers of Earth and Moon are at r = 0 and r=R respectively. Here R is the distance between the Earth and Moon. As usual, the potential energy shall be zero at infinity.

b)Using calculus, find the position between Earth and Moon where the Potential Energy is at its maximum.
C) Calculate the potential energy that the spacecraft has at that point and express the result as a fraction of the energy that the spacecraft has when stationary at the Earth's surface.

Thanks very much,
 
Physics news on Phys.org
a) just add the potential of the Earth [tex]-\frac{GM}{r^2}[/tex]
and the potential of the moon [tex]-\frac{Gm}{|r^2+R^2|}[/tex]

b) now, you are required to find for what r, there's a extremum - meaning when does the derivative equals zero.

c) just put that point you found in the formula to find what's the energy of this point!
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
3K
Replies
21
Views
3K
Replies
3
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 3 ·
Replies
3
Views
6K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
2
Views
4K
  • · Replies 8 ·
Replies
8
Views
11K