Figuring out angular velocity from θ = 2.0 + 4.0t^2 + 2.0t^3

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SUMMARY

The discussion focuses on calculating angular velocity and acceleration from the angular position function θ = 2.0 + 4.0t² + 2.0t³. The angular velocity is derived using the formula w = dθ/dt, resulting in w = (8.0 rad/s²)t + (6.0 rad/s³)t². The participants also explore the angular position at t = 0, which is 2.0 radians, and the angular acceleration at t = 2.0 s, confirming that the angular acceleration is not constant due to the presence of the t² term in the angular velocity equation.

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Homework Statement



The angular position of a point on a rotating wheel is given by θ = 2.0 + 4.0t2 + 2.0t3, where θ is in radians and t is in seconds. At t = 0, what are (a) the point's angular position and (b) its angular velocity? (c) What is its angular velocity at t = 4.0 s? (d) Calculate its angular acceleration at t = 2.0 s. (e) Is its angular acceleration constant?

Homework Equations



w = dθ/dt I am stuck on figuring out how to angular velolcity is:

(8.0rad/s^2)t + (6.0rad/s^3)t^2

as my professor put it, its buggin me how i can't put two and two together.

The Attempt at a Solution

 
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Stonem42 said:
w = dθ/dt I am stuck on figuring out how to angular velolcity is:

I'm stuck on what you're stuck on. What?
 

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