Find a 2 by 2 matrix such that when cubed, is equal to the identity matrix

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To find a 2 by 2 matrix that, when cubed, equals the identity matrix but is not the identity matrix itself, a linear transformation involving rotation is suggested. Specifically, rotating the plane by 120 degrees three times returns any vector to its original position, implying the matrix represents this transformation. The discussion emphasizes visualizing the rotation of points in the plane, particularly how the point (1,0) transforms under such rotations. Understanding the rotation matrix is crucial, as it provides the necessary structure to achieve the desired cubing property. The key takeaway is to explore the geometric implications of rotation in R2 to derive the matrix.
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Homework Statement


Find a 2 by 2 matrix such that when cubed, is equal to the identity matrix. This matrix cannot be equal to the identity matrix unless it is cubed.

So for example:
B3 = [1 0;0 1]
but
B≠[1 0;0 1]

The Attempt at a Solution


The professor told us that we have to use a linear transformation where you rotate it three times by 120o. The problem I have is that I cannot visualize how such rotations can solve the problem. Also I don't even know what to rotate. If anyone knows what to do it would be greatly appreciated, thanks!
 
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What happens when you rotate a vector x by 120 degrees about the origin three times?
 
You get back to the original vector. But i still can't relate this to cubing a matrix.
 
Think "rotation matrix."
 
theBEAST said:

Homework Statement


Find a 2 by 2 matrix such that when cubed, is equal to the identity matrix. This matrix cannot be equal to the identity matrix unless it is cubed.

So for example:
B3 = [1 0;0 1]
but
B≠[1 0;0 1]

The Attempt at a Solution


The professor told us that we have to use a linear transformation where you rotate it three times by 120o. The problem I have is that I cannot visualize how such rotations can solve the problem. Also I don't even know what to rotate. If anyone knows what to do it would be greatly appreciated, thanks!

what you would be rotating is the entire plane, or R2. such a rotation would take the point (x,y) = (1,0) to the point (x',y') = (cosθ,sinθ). that "almost" gives you the matrix right there. use geometry to see if you can figure out where (0,1) might rotate to.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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