MHB Find A,B,C for Factorial Equation

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To solve the factorial equation ABC = A! + B! + C!, it is established that A, B, and C cannot be 7 or higher, as their factorials exceed three-digit numbers. The discussion emphasizes the need for a systematic approach using the properties of factorials and the constraints of three-digit products. Participants inquire about the specific theorems, definitions, or axioms applicable to the problem, indicating a desire for a rigorous mathematical framework. The conversation highlights the importance of understanding factorial growth rates in finding suitable values for A, B, and C. Ultimately, the discussion seeks clarity on the mathematical principles involved in solving the equation.
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find A,B,C such that:

ABC= A!+B!+C!
 
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hint
[sp] since 7!= 7x6x5x4x3x2x1=5040 none of the A,B,C CAN be 7,8,9 because 5040 is a 4 digit no and we are looking for a 3 digit no[/sp]
 
Because this is a 3 digit number each digit shall be < 7 as 7! is a 4 digit number that is 5040
Now no digit can be 6 because 6! = 720 so abc >700 so aother digit becomes 7
Largest digit has be 5 because if largest digit is 4 or more we have $ABC \le 72( 3 * 4!)$
So one digit is 5
Now 5!= 120
2 digits cannot be 5 because 5! + 5! = 240 and one dgit has to be 2 and it does not satisfy.
So we have 1 digit 5 and anothee digit A = 1.
B cannot be 5 because then largest C is 4 and sum <= 145 but b =5 makes abc > 150
So C is 5 and we have 100 + 10 * B + 5 = 1 + B! + 120 $ but tying different values B = 4 so number 145
 
kaliprasad said:
Because this is a 3 digit number each digit shall be < 7 as 7! is a 4 digit number that is 5040
Now no digit can be 6 because 6! = 720 so abc >700 so aother digit becomes 7
Largest digit has be 5 because if largest digit is 4 or more we have $ABC \le 72( 3 * 4!)$
So one digit is 5
Now 5!= 120
2 digits cannot be 5 because 5! + 5! = 240 and one dgit has to be 2 and it does not satisfy.
So we have 1 digit 5 and anothee digit A = 1.
B cannot be 5 because then largest C is 4 and sum <= 145 but b =5 makes abc > 150
So C is 5 and we have 100 + 10 * B + 5 = 1 + B! + 120 $ but tying different values B = 4 so number 145
very good but can you explicity mention which are the theorem ,definitions or axiom used to solve the above?
 
solakis said:
very good but can you explicity mention which are the theorem ,definitions or axiom used to solve the above?
I have used the properties of factorial and positional value of numbers . other than that if you want what explicit prpoperties I have used it is nothing.
 
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