Coefficient of Friction: Finding in a Factory

  • Context: MHB 
  • Thread starter Thread starter Shah 72
  • Start date Start date
  • Tags Tags
    Friction Mechanics
Shah 72
MHB
Messages
274
Reaction score
0
In a factory, a machine picks up a box by clamping it on both sides. The box of mass 4kg is held clamped on both sides by identical clamps with the contacts horizontal. The machine provides a contact force of 50N with each clamp. Find the minimum coefficient of friction between each clamp and the box for the box not to slip.
 
Mathematics news on Phys.org
have you sketched a free body diagram?

In the vertical direction ...

\[ \sum f_{s \, max} = mg \]
 
skeeter said:
have you sketched a free body diagram?

In the vertical direction ...

\[ \sum f_{s \, max} = mg \]
Yeah I did that. 40=coefficient of friction ×(50+50).
Coefficient of friction =0.4
 
skeeter said:
have you sketched a free body diagram?

In the vertical direction ...

\[ \sum f_{s \, max} = mg \]
Thank you so much!
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
5
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K