Find acceleration vector of a car travelling on a circular path

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SUMMARY

The discussion focuses on calculating the acceleration vector of a car traveling on a circular path with a radius derived from the arc length of 235 meters completed in 36.0 seconds. The radial acceleration is determined using the formula arad = V² / r, where the velocity V is calculated as 6.53 m/s. The final radial acceleration at point B is found to be 0.285 m/s² in the direction of the unit vector \hat{i}. Additionally, the velocity vector at point B is confirmed to be (6.53 m/s) \hat{j}.

PREREQUISITES
  • Understanding of circular motion and acceleration concepts
  • Familiarity with the equations of motion, specifically arad = V² / r
  • Ability to perform unit vector notation in physics
  • Basic knowledge of calculating velocity from distance and time
NEXT STEPS
  • Learn about centripetal acceleration and its applications in circular motion
  • Study the derivation of the formulas for radial acceleration in circular paths
  • Explore the concept of tangential acceleration and its absence in uniform circular motion
  • Investigate the relationship between angular velocity and linear velocity in circular motion
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Students studying physics, particularly those focusing on mechanics and circular motion, as well as educators seeking to clarify concepts related to acceleration vectors in uniform circular motion.

Phys121VIU
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Homework Statement


A car is traveling eastward turns north by traveling in a circular path at uniform speed as shown in the picture. the length of arc ABC is 235m and the car completes the turn in 36.0s

a) Find the acceleration vector of the car when it is at B. Express answer in terms of unit vectors\hat{i} and \hat{j}


Homework Equations


arad = V2 / r = 149.6m

circumference of a circle = 2nr

The Attempt at a Solution



Because the car is traveling at uniform speed, there is no tangential acceleration conponent, just radial acceleration. From there I found the radius of the arc the car is traveling on

r = [(235) x 2] / ∏

So radial acceleration = [V2] / r

but velocity isn't given..so there are two unknowns and therefore i can't solve for arad, therefore i am stuck.. any hints would be appreciated!
 

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Phys121VIU said:

Homework Statement


A car is traveling eastward turns north by traveling in a circular path at uniform speed as shown in the picture. the length of arc ABC is 235m and the car completes the turn in 36.0s

a) Find the acceleration vector of the car when it is at B. Express answer in terms of unit vectors\hat{i} and \hat{j}


Homework Equations


arad = V2 / r = 149.6m

circumference of a circle = 2nr

The Attempt at a Solution



Because the car is traveling at uniform speed, there is no tangential acceleration conponent, just radial acceleration. From there I found the radius of the arc the car is traveling on

r = [(235) x 2] / ∏

So radial acceleration = [V2] / r

but velocity isn't given..so there are two unknowns and therefore i can't solve for arad, therefore i am stuck.. any hints would be appreciated!

Can you work out something with bolded text?
 
I see, its traveling at constant velocity so it is the same all along the arc.

velocity = d / t

= 235m / 36.0s

= 6.53m/s

and with that, the radial acceleration can be found :

arad = v2 / r

= (6.53m/s)2 / 149.6m

= 0.285 m/s2 = 0.285 m/s2 \hat{i}


Thank you!
EDIT***

b) Find the velocity vector at B. Express answer in terms of \hat{i} and \hat{j}

This is part two..i just want to see if I am on the right track..

Is the velocity at B = (6.53m/s) \hat{j} ??

(I didnt think these questions would be this simple..):S
 
Last edited:

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