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Find the radius of a particle's circular path

  1. Jun 9, 2017 #1
    1. The problem statement, all variables and given/known data
    A particle moves along a circular path over a horizontal xy plane at a constant speed. At time t1= 3.00s, its acceleration vector is given by (3i-5j) m/s^2. At time t2=7.00 s, its acceleration is given by (-3i+5j) m/s^2.
    Find the radius of the particle's circular path.

    2. Relevant equations
    centripetal acceleration = v^2/r

    3. The attempt at a solution
    Stumbling around for about an hour with no clue what to do... left me with nothing to show for.
     
  2. jcsd
  3. Jun 9, 2017 #2

    BvU

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    Hello David, :welcome:

    Doesn't count as an attempt at solution; according to the PF rules we're not allowed to assist in such a case.

    But for a first post I'll stick out my neck :rolleyes:: You have two acceleration vectors; notice anything particular about them ? Could that help you towards another expression involving ##v## and ##r## ?
     
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