MHB Find all possible solutions of c and d

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The equation a^2 + b^2 + c^2 = d^2 is analyzed with a=70 and b=61, leading to the equation d^2 - c^2 = 8621. By factoring 8621 into pairs, solutions for c and d can be derived, specifically (d, c) = (4321, 4320) and (135, 98). The method involves equating the factors to d+c and d-c, allowing for the calculation of possible integer values. Ultimately, two sets of solutions are confirmed: (4311, 4310) and (135, 98).
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$$if : a^2 + b^2 +c^2 = d^2 $$
where a,b c and d both are positive integers
if a=70 ,b=61
find all posible values of c and d
 
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we have $70^2 + 61^2 + c^2 = d^2$
or $4900 +3721 + c^2 -= d^2$
or $d^2-c^2 = 8621$
or ($d+c)(d-c) = 8621$
to solve the same you can put 8621 as product of 2 numbers (one case 8621 * 1$ equiate one to d +c and another to d- c and solve for c and d. by choosing all pair of numbers fot erach pair one set of c d can be obtained
 
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kaliprasad said:
we have $70^2 + 61^2 + c^2 = d^2$
or $4900 +3721 + c^2 -= d^2$
or $d^2-c^2 = 8621$
or ($d+c)(d-c) = 8621$
to solve the same you can put 8621 as product of 2 numbers (one case 8621 * 1$ equiate one to d +c and another to d- c and solve for c and d. by choosing all pair of numbers fot erach pair one set of c d can be obtained
(d+c)(d-c)=8621
the only solution is
d=4321
c=4320
 
(d+c)(d-c)=8621=(8621)(1)=(233)(37)
the solution is
(d,c)=(4321,4320),(135,98)#
 
kaliprasad said:
we have $70^2 + 61^2 + c^2 = d^2$
or $4900 +3721 + c^2 -= d^2$
or $d^2-c^2 = 8621$
or ($d+c)(d-c) = 8621$
to solve the same you can put 8621 as product of 2 numbers (one case 8621 * 1$ equiate one to d +c and another to d- c and solve for c and d. by choosing all pair of numbers fot erach pair one set of c d can be obtained
Thaks for your answer
Kaliprasad

Albert
 
Albert391212 said:
(d+c)(d-c)=8621=(8621)(1)=(233)(37)
the solution is
(d,c)=(4321,4320),(135,98)#
(d+c)(d-c)=8621=(8621)(1)=(233)(37)
the solution is
(d,c)=(4311,4310),(135,98)#
sorry again
I have a poor calculation
we have two sets of solution
d=135 or 4311
c=98 or 4310
(d,c)=(4311,4310),(135,98)#
 

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