MHB Find All Real Solutions: Is x = 0 a solution to the equation?

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The discussion confirms that x = 0 is indeed a solution to the equation x = rt{3x + x^2 - 3•rt{3x + x^2}}. The calculations show that substituting x = 0 into the equation simplifies correctly to 0 = 0, validating the solution. The method used to derive this solution is also affirmed as correct. Participants emphasize the importance of verifying solutions to ensure they satisfy the original equation. The conclusion is that x = 0 is a valid real solution.
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Find all the real solutions of the equation.

Let rt = root

x = rt{3x + x^2 - 3•rt{3x + x^2}}

(x)^2 = [rt{3x + x^2 - 3•rt{3x + x^2}}]^2

x^2 = 3x + x^2 - 3•rt{3x + x^2}

x^2 - x^2 - 3x = - 3•rt{3x + x^2}

-3x = -3•rt{3x + x^2}

-3x/-3 = rt{3x + x^2}

x = rt{3x + x^2}

(x)^2 = [rt{3x + x^2}]^2

x^2 = 3x + x^2

x^2 - x^2 = 3x

0 = 3x

0/3 = x

0 = x

Correct?
 
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RTCNTC said:
Find all the real solutions of the equation.

Let rt = root

x = rt{3x + x^2 - 3•rt{3x + x^2}}

(x)^2 = [rt{3x + x^2 - 3•rt{3x + x^2}}]^2

x^2 = 3x + x^2 - 3•rt{3x + x^2}

x^2 - x^2 - 3x = - 3•rt{3x + x^2}

-3x = -3•rt{3x + x^2}

-3x/-3 = rt{3x + x^2}

x = rt{3x + x^2}

(x)^2 = [rt{3x + x^2}]^2

x^2 = 3x + x^2

x^2 - x^2 = 3x

0 = 3x

0/3 = x

0 = x

Correct?

Your method is correct. You must also check that the answer you have found actually works to make the equation true.
 
Check:

Let x = 00 = rt{3(0) + (0)^2 - 3•rt{3(0) + (0)^2}}

0 = rt{0 + 0 - 3rt{0 + 0}}

0 = rt{0 + 0 - 3rt{0}}

0 = rt{0 + 0 - 0}

0 = rt{0}

0 = 0

It checks to be true.
 
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