Find an expression for the attenuation from the eqn given

Click For Summary
SUMMARY

The discussion centers on deriving an expression for the attenuation coefficient, ki, from the equation k2=εμω2-iωμσ. The final expression for ki is given as ki=ω(εμ/2)1/2[(1+(σ2/ω2ε2))1/2)-1]1/2. The user initially attempted to equate the real and imaginary parts of the equation but encountered a quartic equation. After receiving guidance, they recognized the problem could be simplified to a quadratic equation, facilitating a clearer solution.

PREREQUISITES
  • Understanding of complex numbers and their applications in wave equations
  • Familiarity with electromagnetic theory, specifically the concepts of permittivity (ε) and permeability (μ)
  • Knowledge of quadratic equations and their solutions
  • Basic grasp of wave propagation and attenuation in materials
NEXT STEPS
  • Study the derivation of wave equations in electromagnetic theory
  • Learn about the physical significance of attenuation coefficients in materials
  • Explore the application of quadratic equations in solving complex problems
  • Investigate the impact of frequency (ω) on wave propagation in different media
USEFUL FOR

Students and professionals in physics and engineering, particularly those focusing on electromagnetic theory, wave propagation, and material science.

BadPhysicistAtWork
Messages
2
Reaction score
0
Poster has been reminded to use the Homework Help Template to organize their HH threads
Having a big issue working through this problem and was wondering if somebody, much smarter than I, could give me a few pointers. Anyway here's the problem:

Given that k2=εμω2-iωμσ

By writing the wave number as k=kr-iki.
Show that ki, which determines attenuation, can be expressed by:
ki=ω(εμ/2)1/2[(1+(σ22ε2))1/2)-1]1/2

I've started by equating real and imaginary parts however I find an impasse where I have a quartic equation.

I'd been incredibly grateful for any answers, thank you in advance!

Just as a quick note, I followed the following process but reached an impasse (may be completely off base here):
k2=εμω2-iωμσ
Substitute k=kr-iki. into the equation which gives;
kr2-2ikrki-ki2=εμω2-iωμσ
Then split into two equations by equating real and imaginary parts;
(1) kr2-ki2=εμω2
(2) εμω2=ωμσ/2ki
Now (2) into (1) gives;
(ωμσ/2ki)2-ki2=εμω2
Then rearranging gives;
ki4+εμω2ki22μ2σ2/4

[EDIT: Realised i'd been a bit of an idiot and missed what should have been quite obvious, thank you for pointing it out!]
 
Last edited:
Physics news on Phys.org
it is a quadratic... set [itex]k_{i} = \alpha[/itex] and us the quadratic equation for [itex]\alpha[/itex] and take the square root...
 
Actually really disappointed i myself for not seeing that... Thank you for that, really made this a lot easier.
 

Similar threads

  • · Replies 26 ·
Replies
26
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K