Find Average Acceleration of a Turning Car in 2.0s | Step-by-Step Guide

[sanado]

Homework Statement

A car traveling north at a speed of 40km/h turns right to head due east at a speed of 30km/h. This change in direction and speed takes 2.0 s. Calculate the average acceleration of the car.

Homework Equations

a = v-u/t

The Attempt at a Solution

Was wondering if you guys could help me with this question. I can find the magnitude quite easily however i cannot find the new direction. Would someone be able to post a detailed guide as to how to get the direction?

 

[Shooting Star]

Write v and u using unit vectors i and j.

 

[sanado]

Sorry mate I'm kind of new to physics. Would you be able to give me some detailed working out (being annotated would help a lot) as to how you come across the acceleration. I no I am asking a lot but its annoying me so much cause i want to learn this before i progress and forget about it

 

[Shooting Star]

Well, uhh...matey, all right.

Choose y-axis toward N and x-axis toward E.

u = 40j and v = 30i.

Average a = change in velocity/time = (v-u)/t = (30i - 40j)/2* 1000/3600 m/s (converting km/h to m/s). Simplify a bit.

You had said that you can find the magnitude quite easily. Still, the magnitude of ai+bj is sqrt(a^2+b^2).