- #1

juju1

## Homework Statement

At one instant a bicyclist is 20.5 m due south of a park's flagpole, going due east with a speed of 14.1 m/s. Then, 3.95 s later, the cyclist is 36.3 m due west of the flagpole, going due north with a speed of 18.3 m/s. For the cyclist in this 3.95 second interval, find each of the following.

## Homework Equations

(a) displacement magnitude and direction:

(b) average velocity magnitude and direction:

(c) average acceleration magnitude and direction:

## The Attempt at a Solution

a)So i found the displacement by the formula sqrt(20.5ihat^2 + 36.3jhat^2) but for some reason i couldn't find the direction. i drew it out, and my resultant vector points NorthWest, i also plugged in inversetan(36.3/20.5) and it was wrong

b) I found the average velocity by taking 20.5ihat and 36.3jhat and dividing that by the time and then plugging it into the equation and got (10.6m/s)...once again, i don't know how to find the direction

c) I am VERY confused on how to find the av.acceleration, i tried taking the average velocity that i found by dividing 20.5ihat and 36.3jhat and dividing that by time but it was wrong..