Find b such that 3sin(x) - 1 = b has one solution in (0,2π)

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TyErd
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the equation 3sinx - 1 = b, where b is a positive real number, has one solution in the interval (0,2pi). The value of b is:

Frankly I have no idea where to even start with this problem.
 
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Hi TyErd! :smile:

(have a pi: π :wink:)

Hint: how many solutions in (0,2π) does 3sinx - 1 = 15 have?

And 3sinx - 1 = 0.5 ? :wink:
 
Um. thnx for the pi. How do you know how many solutions there are?
 
TyErd said:
Um. thnx for the pi. How do you know how many solutions there are?

Draw a graph and find out.

Get on with it!​
 
alright I've drawn the graph, so what parts of the graph do i have to look at to know how many solutions there?
 
Which parts? Umm...

If I asked you to find out how many solutions there are to [itex]x^2=10[/itex] how would you go about doing that by looking at a graph?
 
TyErd said:
alright I've drawn the graph, so what parts of the graph do i have to look at to know how many solutions there?
And you should be looking only at the part of the graph on the interval [0, 2π].
 
so when it says solutions, should i be looking at the x intercepts?
 
TyErd said:
alright I've drawn the graph, so what parts of the graph do i have to look at to know how many solutions there?

What is the graph that you have drawn? Specifically, what is the formula of the function you have graphed?
 
I tried to draw 3sinx-1=15 by taking 15 onto the other side but I've just realized that isn't right. How do you graph an equation that equals a number?
 
Graph [itex]15=3sinx-1[/itex]
Then graph [itex]y=15[/itex]

Do you see how if you tried to solve these two equations simultaneously, you would get [itex]15=3sinx-1[/itex]?

Are there any intersections between the two functions?

Now, can you find any number b (such as 15) that makes it such that the equation [itex]3sinx-1=b[/itex] has only 1 real solution in the interval between 0 and 2π?
This is the same as saying for what number b will the function [itex]y=b[/itex] intersect the function [itex]y=3sinx-1[/itex] only once in the interval [itex](0,2\pi)[/itex]?
 
Thankyouuu! i get it finally, you made it so much easier. thnx