Find Cos2A: sinA=-1/3, pi<A<3pi/2

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SUMMARY

To find Cos2A given that sinA = -1/3 and the interval π ≤ A ≤ 3π/2, utilize the identity cos(2A) = 1 - sin²(A). First, calculate sin²(A) which equals (1/3)² = 1/9. Then, substitute this value into the identity to find cos(2A) = 1 - 1/9 = 8/9. The solution confirms that the approach using trigonometric identities is efficient for this problem.

PREREQUISITES
  • Understanding of trigonometric identities, specifically cos(2A) and sin²(A).
  • Knowledge of the unit circle and the behavior of sine and cosine functions within specified intervals.
  • Ability to perform basic algebraic manipulations and substitutions.
  • Familiarity with the concept of inverse trigonometric functions, particularly sin⁻¹.
NEXT STEPS
  • Study the derivation and applications of trigonometric identities, focusing on double angle formulas.
  • Explore the unit circle to better understand the sine and cosine values in different quadrants.
  • Practice solving trigonometric equations within specified intervals to enhance problem-solving skills.
  • Learn about the implications of sine and cosine values in real-world applications, such as wave functions.
USEFUL FOR

Students studying trigonometry, mathematics educators, and anyone looking to strengthen their understanding of trigonometric identities and equations.

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Homework Statement


Find Cos2A if sinA= -1/3 and pi< (or equal to) A < (or equal to) 3pi/2


Homework Equations





The Attempt at a Solution


Do i use sin-1 to find when sin equals -1/3
 
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Yes, you can do that, that's the simple way. Take note of where your answer occurs as there are 2 points where sin(x) = -1/3. The question tells you the domain of A.
 
That's the hard way. The easy way is to use the a identity that expresses cos(2A) in terms of sin(A).
 
You should use the identity cos2A = cos2A - sin2A and

cos2A = 1 - sin2A

Regards.
 

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