Find Cos2A: sinA=-1/3, pi<A<3pi/2

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Homework Help Overview

The problem involves finding Cos2A given that sinA = -1/3 within the interval pi ≤ A ≤ 3pi/2. The context is trigonometric identities and their application in specific domains.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss using the inverse sine function to determine the angles corresponding to sinA = -1/3, while noting the specified domain. Others suggest using trigonometric identities to find Cos2A directly from sinA.

Discussion Status

The discussion is active with various approaches being explored, including the use of inverse functions and trigonometric identities. Some participants have provided guidance on how to relate sinA to Cos2A without reaching a consensus on the preferred method.

Contextual Notes

Participants are considering the implications of the specified interval for A and how it affects the values of sinA and Cos2A. There is an emphasis on the identity relationships in trigonometry.

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Homework Statement


Find Cos2A if sinA= -1/3 and pi< (or equal to) A < (or equal to) 3pi/2


Homework Equations





The Attempt at a Solution


Do i use sin-1 to find when sin equals -1/3
 
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Yes, you can do that, that's the simple way. Take note of where your answer occurs as there are 2 points where sin(x) = -1/3. The question tells you the domain of A.
 
That's the hard way. The easy way is to use the a identity that expresses cos(2A) in terms of sin(A).
 
You should use the identity cos2A = cos2A - sin2A and

cos2A = 1 - sin2A

Regards.
 

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