Find difference in echo times, doppler shift?

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SUMMARY

The discussion centers on calculating the difference in echo times for a bat using echolocation at a frequency of 41 kHz to track an insect. The bat initially detects the insect at a distance of 34 cm and later at 44 cm. The speed of sound is established at 343 m/s, leading to echo time calculations of 0.0019 seconds for 34 cm and 0.0026 seconds for 44 cm. The difference in echo times is determined to be 0.0007 seconds.

PREREQUISITES
  • Understanding of echolocation principles
  • Knowledge of the speed of sound in air (343 m/s)
  • Familiarity with basic physics equations related to time and distance
  • Concept of Doppler shift and its application in sound
NEXT STEPS
  • Study the principles of echolocation in bats
  • Learn about the Doppler effect in sound waves
  • Explore the calculation of echo times using distance and speed of sound
  • Investigate the application of radar equations in real-world scenarios
USEFUL FOR

Students studying physics, particularly in topics related to sound waves and echolocation, as well as educators looking for practical examples of Doppler effect applications.

Angie_Agnes
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Homework Statement


A bat is pursuing an insect, and using echolocation of 41 kHz sound waves to track the insect. The insect is initially 34 cm from the bat but then moves to a distance of 44 cm as it tries to escape. What is the difference in the two echo times that the bat measures?


Homework Equations


I'm not sure... is this a doppler shift question? the book has a few sentences about bats using reflection time and doppler effect to judge distances of objects.

This is an equation for radar: Ltot=vΔt
λ=v/f

Doppler shift (moving away from observer)
Fobs=(fsource)/{1+(Vsource/Vsound)}


The Attempt at a Solution


I attempted to find time by using the Ltot=vΔt equation. 2(.34)=343t -> t=.0019s
2(.44)=343t -> t=.0026s. Obviously wrong. Don't know where to start. Please help.
 
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I don't think it is a doppler effect question. I think it is just two echo times.
You need a value for the speed of sound
 
the speed of sound is 343m/s
 
Now calculate the time to echo from 34cm, then from 44cm.
The difference??
 
had a miscalculation the first time I did it. Thanks.
 

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