Find displacement, time and velocity

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SUMMARY

The discussion focuses on the physics of a rocket's motion under constant acceleration and the effects of gravity. The rocket accelerates upward at 2.25 m/s² for 15.4 seconds, reaching a maximum height of 266.8 meters before the engines fail. Upon engine failure, the rocket's velocity just before impact is calculated to be -72.3 m/s, indicating downward motion. The final question regarding the time taken to crash after engine failure can be solved using kinematic equations.

PREREQUISITES
  • Understanding of kinematic equations for uniformly accelerated motion
  • Knowledge of gravitational acceleration (9.81 m/s²)
  • Familiarity with the concept of maximum height in projectile motion
  • Basic algebra for solving quadratic equations
NEXT STEPS
  • Learn how to apply kinematic equations to solve for time of flight after engine failure
  • Study the concept of free fall and its equations of motion
  • Explore the implications of initial velocity and acceleration on projectile motion
  • Investigate the effects of air resistance on rocket motion
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Students studying physics, educators teaching kinematics, and anyone interested in the dynamics of rocket launches and free-fall motion.

kari82
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A rocket takes off vertically from the launchpad with no initial velocity but a constant upward acceleration of 2.25 m/s2. At 15.4 s after blastoff, the engines fail completely so the only force on the rocket from then on is the pull of gravity.
(a) What is the maximum height the rocket will reach above the launchpad?
(b) How fast is the rocket moving at the instant before it crashes onto the launchpad?
(c) How longer after engine failure does it take for the rocket to crash onto the launchpad?


a)
deltay=vi(t)+1/2(a)(t)^2
deltay=0(15.4)+1/2(2.25m/s^2)(15.4s^2)
deltay=266.8m

b)Vf^2=vi^2+2(g)(deltay)
vf=+/-squareroot(2(-9.8m/s^2)(-266.8m))
vf=-72.3m/s

Can anyone tell me if what I'm doing is correct? and can i get a hint on how to solve question (c)?

Thanks!
 
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v= u + at
and you said that the maximum velocity the rocket reaches is 72.3ms
the rocket from it's max height is accelerating towards Earth at a speed of 9.81ms.

there's your two values. just plug them into the equation.
 
Thank you!
 

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