MHB Find Function f: Area Under Curve A & Above 3A, \(f(x_1)=y_1\)

  • Thread starter Thread starter Dustinsfl
  • Start date Start date
  • Tags Tags
    Function
Click For Summary
To find a function f where the area under the curve is A and the area above it is 3A, the equations to solve are \(\int_0^{x_1} f dx = A\) and \(\int_0^{x_1} (y_1 - f) dx = 3A\). An attempt was made to relate these areas by manipulating the integrals, leading to the equation \(\int_0^{x_1} (y_1 - 4f) dx = 0\), but this approach did not yield a solution. It was noted that there are infinitely many functions that satisfy the area conditions, with the only confirmed relationship being \(\int_0^x f(x) dx = \frac{x_1 y_1}{4}\). The discussion highlights the complexity of finding a specific function under these constraints.
Dustinsfl
Messages
2,217
Reaction score
5
I want to find a function f where the area under the curve is A and the area above it is 3A and \(f(x_1) = y_1\).
\[
\int_0^{x_1}fdx = A
\]
and
\[
\int_0^{x_1}(y_1 - f)dx = 3A
\]
What I tried was taking
\begin{align}
\int_0^{x_1}(y_1 - f)dx &= 3\int_0^{x_1}fdx\\
\int_0^{x_1}(y_1 - 4f)dx &= 0
\end{align}
but this doesn't seem to go anywhere.
 
Physics news on Phys.org
There are infinitely many such functions. The only thing that you know for sure is that $\int_0^xf(x)\,dx=x_1y_1/4$.
 
Thread 'Problem with calculating projections of curl using rotation of contour'
Hello! I tried to calculate projections of curl using rotation of coordinate system but I encountered with following problem. Given: ##rot_xA=\frac{\partial A_z}{\partial y}-\frac{\partial A_y}{\partial z}=0## ##rot_yA=\frac{\partial A_x}{\partial z}-\frac{\partial A_z}{\partial x}=1## ##rot_zA=\frac{\partial A_y}{\partial x}-\frac{\partial A_x}{\partial y}=0## I rotated ##yz##-plane of this coordinate system by an angle ##45## degrees about ##x##-axis and used rotation matrix to...

Similar threads

  • · Replies 3 ·
Replies
3
Views
3K
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 24 ·
Replies
24
Views
3K
  • · Replies 20 ·
Replies
20
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K