Find Initial Velocity of Ball with Time: 3.37

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To find the initial velocity of a ball using the time of 3.37 seconds, the formula dy = 1/2(a)(t)^2 is not directly applicable without knowing the acceleration. The discussion highlights the need for clarity on the question being asked, as the context of motion (upward or downward) affects the calculations. The calculated velocity of 33.026 m/s is questioned, indicating potential confusion about the correct approach. Understanding the relationship between time, acceleration, and initial velocity is crucial for accurate results. Clearer parameters of the problem would lead to a more precise calculation.
jubbly
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Hey guys, I was wondering how to find the initial velocity of a ball going up with only the time.

The time I have is 3.37, would I use the formula: dy=1/2(a)(t)^2
to find the initial velocity?

I got 33.026 m/s but I don't think that's right.
 
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What is the actual question? It would provide for a clearer understanding.
 
Thread 'Correct statement about size of wire to produce larger extension'

Thread 'Correct statement about size of wire to produce larger extension'

The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...
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