Find inverse for f(x)= x/(1+x)

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SUMMARY

The forum discussion focuses on finding the inverse of the function f(x) = x/(1+x). The correct inverse function is y = x/(1-x), derived by manipulating the original equation. Participants emphasize the importance of not switching variables during the process and suggest isolating x to solve for the inverse. The discussion concludes with a successful resolution of the problem, highlighting the collaborative effort in problem-solving.

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Homework Statement


Show that the functions f are one-to-one and calculate the inverse function.

Homework Equations


f(x)= x/(1+x) (It is the equation I am having trouble with)

The Attempt at a Solution


I know the solution is y= x/(1-x) But no idea how to solve it.

My attempt:
x(1+y)=y or x+xy=y

y+y=x/x
 
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jimjames said:

Homework Statement


Show that the functions f are one-to-one and calculate the inverse function.

Homework Equations


f(x)= x/(1+x) (It is the equation I am having trouble with)

The Attempt at a Solution


I know the solution is y= x/(1-x) But no idea how to solve it.

My attempt:
x(1+y)=y or x+xy=y
Start with ##y = \frac x {1 + x}##
What's the first thing you need to do?
jimjames said:
y+y=x/x
I'm not sure what you did here.
 
Where did you get y = x/(1+x) ?

What i normally do is
f(x) = x/(1+x) <=> x=f^-1(y)
f(y) = y/(1+y) <=> y=f^-1(x)

x=y/(1+y)
y=x+xy

And now I'm stuck
 
jimjames said:
Where did you get y = x/(1+x) ?

What i normally do is
f(x) = x/(1+x) <=> x=f^-1(y)
f(y) = y/(1+y) <=> y=f^-1(x)
The above doesn't help you with this problem. All you're doing is manipulating symbols.
jimjames said:
x=y/(1+y)
In the line above, all you did was switch x and y.
jimjames said:
y=x+xy
How did you get the equation above?
jimjames said:
And now I'm stuck
Start with y = ##\frac x {1 + x}##

For this problem DO NOT switch the variables x and y.
DO solve for x in the equation just above. In other words, x should appear only on one side of the equation.
 
y(1+x)=x
1+x=x/y
 
Last edited:
jimjames said:
y(1+x)=x
1+x=x/y
OK.

Now divide both sides by x.
 
jimjames said:
Where did you get y = x/(1+x) ?
That's the function you're trying to find the inverse of.
Multiplying both sides of this equation by 1 + x gives you the equation just below.
jimjames said:
y(1+x)=x
1+x=x/y
SammyS said:
OK.

Now divide both sides by x.
It's probably simpler to expand y(1 + x), get all terms that involve x on one side, and then isolate x.
 
jimjames said:

Homework Statement


Show that the functions f are one-to-one and calculate the inverse function.

Homework Equations


f(x)= x/(1+x) (It is the equation I am having trouble with)

The Attempt at a Solution


I know the solution is y= x/(1-x) But no idea how to solve it.

My attempt:
x(1+y)=y or x+xy=y

y+y=x/x

Why do you call this a "transcendental function"? It is just about as far from transcendental as you can get.
 
Ray Vickson said:
Why do you call this a "transcendental function"? It is just about as far from transcendental as you can get.
I changed the title a while ago for that very reason.
 
  • #10
jimjames said:
Where did you get y = x/(1+x) ?

What i normally do is
f(x) = x/(1+x) <=> x=f^-1(y)
f(y) = y/(1+y) <=> y=f^-1(x)

x=y/(1+y)
y=x+xy

And now I'm stuck
Subtract xy from both sides: y- xy= y(1-x)= x
 
  • #11
Managed to solve this late yesterday.
Thanks for trying to help.:smile:
 

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