Find Lap Time: Is 0.8 Sec Correct?

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SUMMARY

The discussion centers on calculating the lap time (T) for a circular track with a radius (r) of 50 meters and a friction coefficient of 0.8. The initial calculation incorrectly yielded a lap time of 0.8 seconds, derived from the formula T = distance/speed, where the speed was calculated as v = r*g*friction. Upon realizing the omission of the square root in the velocity calculation, the corrected lap time was determined to be approximately 16 seconds, aligning with expectations for such a scenario.

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Homework Statement



Friction=0.8
r=50 m
T=?

Homework Equations



T=distance/speed

Perimeter=2*pi*r

Fc=(mv^2)/r

Ffriction=m*g*friction

The Attempt at a Solution



Perimeter
2*3.14*50=314

Fc=Ffriction

(mv^2)/r=m*g*friction

v=r*g*friction

= 50*9.82*0.8=391.8

T=314/391.8 = 0.8 s

Is this correct? Seems a bit wrong to me :S
 
Last edited:
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forgot to take the square root of velocity.
 
andrien said:
forgot to take the square root of velocity.

Ah! That gives me almost 16 sec, which makes more sense

Thank you!
 

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