Find Lap Time: Is 0.8 Sec Correct?

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The discussion revolves around calculating lap time using a friction coefficient of 0.8 and a radius of 50 meters. The initial calculation yielded a lap time of 0.8 seconds, which seemed incorrect. Upon realizing the need to take the square root of the velocity in the formula, the recalculated lap time approached 16 seconds, aligning better with expectations. This adjustment highlights the importance of correctly applying physics equations in motion problems. The final conclusion indicates that the original lap time calculation was indeed incorrect.
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Homework Statement



Friction=0.8
r=50 m
T=?

Homework Equations



T=distance/speed

Perimeter=2*pi*r

Fc=(mv^2)/r

Ffriction=m*g*friction

The Attempt at a Solution



Perimeter
2*3.14*50=314

Fc=Ffriction

(mv^2)/r=m*g*friction

v=r*g*friction

= 50*9.82*0.8=391.8

T=314/391.8 = 0.8 s

Is this correct? Seems a bit wrong to me :S
 
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forgot to take the square root of velocity.
 
andrien said:
forgot to take the square root of velocity.

Ah! That gives me almost 16 sec, which makes more sense

Thank you!
 
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