Find Magnitude of FA & FB in 8.27 kg Object

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The discussion focuses on calculating the magnitudes of two forces, FA and FB, acting on an object with a mass of 8.27 kg. When both forces act in the same direction (due east), the object's acceleration is 0.57 m/s². In contrast, when FA acts due east and FB acts due west, the acceleration reduces to 0.35 m/s². The problem can be solved using Newton's second law, resulting in two equations with two unknowns to find the magnitudes of FA and FB.

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Hey guys, need a little help. Can someone point me in the right direction for this question? I just need to know where to start.

Two forces FA and FB are applied to an object whose mass is 8.27 kg. The larger force is FA. When both forces point due east, the object's acceleration has a magnitude of 0.57 m/s2. However, when FA points due east and FB points due west, the acceleration is 0.35 m/s2, due east.

(a) Find the magnitude of FA
(b) Find the magnitude of FB
 
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Hi JJones_86,

JJones_86 said:
Hey guys, need a little help. Can someone point me in the right direction for this question? I just need to know where to start.

Two forces FA and FB are applied to an object whose mass is 8.27 kg. The larger force is FA. When both forces point due east, the object's acceleration has a magnitude of 0.57 m/s2. However, when FA points due east and FB points due west, the acceleration is 0.35 m/s2, due east.

(a) Find the magnitude of FA
(b) Find the magnitude of FB

How are the forces related to acceleration?
 
case one

i-Fnet,x= FA cos(0)+FBcos(0)=ma

0- because they are in the orginal x-axis and pointed to the right

a=0.57 m/s2


case two

do the same thing what i did in case one

Fnet,x= FA cos(0)+FA cos(180)=ma,,, (a here is .35)
180 because it is ponited to the left

u have two equation with two unkowns
 

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