Find Max Speed Before String Breaks for 6 kg Rock on Rope

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SUMMARY

The discussion focuses on calculating the maximum speed of a 6 kg rock spinning in a circle with a radius of 1.5 meters before the tension in the string exceeds 75 N. The user applies the formula for net force (Fnet = ma) and centripetal acceleration (a = 4π²R/T²) to derive the relationship between gravitational force and tension. The calculations lead to a period (T) of approximately 2.2 seconds. The user seeks confirmation on using the acceleration formula (a = v²/R) to find the maximum speed.

PREREQUISITES
  • Understanding of Newton's second law (Fnet = ma)
  • Knowledge of centripetal acceleration (a = 4π²R/T²)
  • Familiarity with the concepts of tension and gravitational force
  • Basic algebra for solving equations
NEXT STEPS
  • Learn how to derive centripetal acceleration from tension in circular motion
  • Study the relationship between period and speed in circular motion
  • Explore the implications of maximum tension in string dynamics
  • Investigate real-world applications of circular motion in physics
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and circular motion, as well as educators looking for examples of tension and acceleration in practical scenarios.

TheronSimon
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Homework Statement


so there's a 6 kg rock spinning in a circle with a string that can with stand a maximum tension of 75 and a radius of 1.5m
and i need to find the maximum speed before the string will break

Homework Equations



Fnet=ma
a=4\pi2R/T2

The Attempt at a Solution


so Fnet =ma and a = 4\pi2R/T2
so Fg = m*4\pi2R/T2
so 6*9.8 = 6*4\pi21.5/T2
so 58.8 = 284.24 / T2
so T = 2.2

no would i be able to use this formula a=4\pi2R/T2 to find the acceleration and then use a= v2/R to get the speed?
 
Last edited:
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anyone?
 
no nothing?
 

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