Find Moment Around A with 3D Vectors: B & C

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    3d Moment
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Homework Help Overview

The discussion revolves around calculating the moment around point A using 3D vectors related to points B and C. The original poster presents a scenario involving a force and its application in a three-dimensional context, specifically focusing on the vectors associated with points A, B, and C.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the appropriate vector to use for calculating the moment about point A, with some uncertainty about the initial calculations and the correct application of the cross product. Questions arise regarding the correct r-vector needed for the moment calculation and the relevance of the force's direction.

Discussion Status

There is an ongoing exploration of the correct approach to find the moment, with participants questioning the initial assumptions and calculations. Some guidance has been offered regarding the necessary vectors and the relationship between force and distance in the context of moment calculation.

Contextual Notes

Participants note the importance of using the correct r-vector that connects point A to the point of force application, emphasizing the need for clarity in the problem setup and the definitions involved.

LeftBrain
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Homework Statement


wbqf13.jpg


A (0,0,0)
B(5,6,1)
C(3,0,4)

|F|= 1919N

Homework Equations

The Attempt at a Solution



Cartesian:
B= {5i + 6j + 1k}
C= {3i + 4k}

rCB ={2i + 6j - 3k}

|rCB| = sqrt(22 + 62 + 32) = 7

Unit vector = rCB / |rCB| = {2/7i + 6/7j - 3/7k}

F = |F| * Unit vector = 1919 {2/7i + 6/7j - 3/7k} = 548.29i + 1644.86j - 822.43k

Now firstly, I'm not sure if I even did the above part correctly, but to find the moment I'm a bit lost and my don't seem to have much in my notes about this...

I think the next step is using cross product, but I'm a bit lost as to which arm to take to find moment about A...

If I use rBA I get:

MA = rBA x F = 6579.44i - 4660.44j - 4934.56k

WELP! Need help!

Cheers LB
 
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LeftBrain said:

Homework Statement


wbqf13.jpg


A (0,0,0)
B(5,6,1)
C(3,0,4)

|F|= 1919N

Homework Equations

The Attempt at a Solution



Cartesian:
B= {5i + 6j + 1k}
C= {3i + 4k}

rCB ={2i + 6j - 3k}

|rCB| = sqrt(22 + 62 + 32) = 7

Unit vector = rCB / |rCB| = {2/7i + 6/7j - 3/7k}

This is not the r-vector for use in calculating the moment about point A. What is the r-vector you need instead?

(Hint: What is the Force pulling on?)
F = |F| * Unit vector = 1919 {2/7i + 6/7j - 3/7k} = 548.29i + 1644.86j - 822.43k

Now firstly, I'm not sure if I even did the above part correctly, but to find the moment I'm a bit lost and my don't seem to have much in my notes about this...

You can always find discussions and examples of how to calculate the moment on the web.
I think the next step is using cross product, but I'm a bit lost as to which arm to take to find moment about A...

If I use rBA I get:

MA = rBA x F = 6579.44i - 4660.44j - 4934.56k

WELP! Need help!

Cheers LB
See above. Remember, the problem asks for the magnitude of the moment, so don't forget that!
 
So I need to use rBC instead?
 
LeftBrain said:
So I need to use rBC instead?
No, you need to use the r-vector which connects point A to the end of the rope pulling on the end of bar AB.

Remember, calculating a Moment requires a Force and some kind of Distance between the force and the axis of rotation caused by the moment.
 

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