Find r'(t)·r''(t) of r(t) = <2e²t, 4e⁻²t, te²t>

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Homework Statement


If r(t) = [tex]\left\langle\[/tex]2e^{2t},4e^{-2t},te^{2t} [tex]\right\rangle[/tex], find r'(t) [tex]\cdot[/tex] r''(t).

Homework Equations


r'(t) = [tex]\left\langle[/tex]4e^{2t},-8e^{-2t},2te^{2t}+e^{2t} [tex]\right\rangle[/tex]
r''(t) = [tex]\left\langle[/tex]8e^{2t},16e^{2t},4te^{2t}+4e^{2t} [tex]\right\rangle[/tex]

The Attempt at a Solution


r'(t) [tex]\cdot[/tex] r''(t) = 32e^{2t} - 128 + 8t^2e^{2t} + 8te^{2t} + 4te^{2t} + 4e^{2t}
r'(t) [tex]\cdot[/tex] r''(t) = 36e^{4t}+8t^2e^{2t}+12te^{2t}-128

I cannot see why my answer is wrong. Please help!
 
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Fixed your post to make it readable:
chickyroger said:

Homework Statement


If [itex]\mathbf{r}(t) = \langle 2e^{2t}, 4e^{-2t}, te^{2t} \rangle[/itex], find [itex]\mathbf{r}'(t)\cdot\mathbf{r}''(t)[/itex].

Homework Equations


[tex]\mathbf{r}'(t) = \langle 4e^{2t},-8e^{-2t},2te^{2t}+e^{2t} \rangle[/tex]
[tex]\mathbf{r}''(t) = \langle 8e^{2t},16e^{2t},4te^{2t}+4e^{2t} \rangle[/tex]

The Attempt at a Solution


[tex]\mathbf{r}'(t) \cdot \mathbf{r}''(t) = 32e^{2t} - 128 + 8t^2e^{2t} + 8te^{2t} + 4te^{2t} + 4e^{2t}[/tex]
[tex]\mathbf{r}'(t) \cdot \mathbf{r}''(t) = 36e^{4t}+8t^2e^{2t}+12te^{2t}-128[/tex]

I cannot see why my answer is wrong. Please help!
You didn't combine the exponentials together correctly.
 
chickyroger said:

Homework Statement


If r(t) = [tex]\left\langle\[/tex]2e^{2t},4e^{-2t},te^{2t} [tex]\right\rangle[/tex], find r'(t) [tex]\cdot[/tex] r''(t).

Homework Equations


r'(t) = [tex]\left\langle[/tex]4e^{2t},-8e^{-2t},2te^{2t}+e^{2t} [tex]\right\rangle[/tex]
This is correct.
r''(t) = [tex]\left\langle[/tex]8e^{2t},16e^{2t},4te^{2t}+4e^{2t} [tex]\right\rangle[/tex][/quote]
This is not but probably just a typo: the second component is [itex]16e^{-2t}[/itex].

The Attempt at a Solution


r'(t) [tex]\cdot[/tex] r''(t) = [tex]32e^{2t} - 128 + 8t^2e^{2t} + 8te^{2t} + 4te^{2t} + 4e^{2t}[/tex]
And you have propogated the typo: the product in the second term is [itex](-8e^{-2t})(16e^{-2t})= -128e^{-2t}[/tex]<br /> <br /> <blockquote data-attributes="" data-quote="" data-source="" class="bbCodeBlock bbCodeBlock--expandable bbCodeBlock--quote js-expandWatch"> <div class="bbCodeBlock-content"> <div class="bbCodeBlock-expandContent js-expandContent "> <b>r'</b>(t) [tex]\cdot[/tex] <b>r''</b>(t) = 36e^{4t}+8t^2e^{2t}+12te^{2t}-128<br /> <br /> I cannot see why my answer is wrong. Please help! </div> </div> </blockquote>[/itex]