Find Solution for Polar to Rectangular Equation

[karush]

Polar to rectangular

$$r=1-2 \sin\left({\theta}\right)$$

$${x}^{2}+{y}^{2}=\sqrt{{x}^{2}+{y}^{2 }}+2y$$

Is this an answer just hard to get $y=$

 

[MarkFL]

You've made a minor sign slip, but think of the graph of the polar equation...would you expect to get $y$ as a function of $x$?

 

[karush]

$${x}^{2}+{y}^{2}=\sqrt{{x}^{2}+{y}^{2 }}-2y$$

So this is the final

 

[MarkFL]

$${x}^{2}+{y}^{2}=\sqrt{{x}^{2}+{y}^{2 }}-2y$$

So this is the final

Yes, that looks good to me. :D