Find Solution to Ship Fuel Problem: 1.0 X 10^5 N Drag

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SUMMARY

The problem involves calculating the distance a nuclear-powered ship can travel per kilogram of fuel, given a drag force of 1.0 X 10^5 N and an engine efficiency of 20%. The fuel consists of enriched uranium with 1.7% of the fissionable isotope 235U, releasing 208 MeV per fission event. The solution concludes that the ship can travel approximately 2.9 X 10^3 km (1800 miles) per kilogram of fuel, demonstrating the application of work done in physics.

PREREQUISITES
  • Understanding of basic physics concepts, particularly work and energy.
  • Knowledge of nuclear fission and isotopes, specifically 235U.
  • Familiarity with energy conversion efficiency in engines.
  • Basic mathematical skills for unit conversion and calculations.
NEXT STEPS
  • Study the principles of work and energy in physics.
  • Learn about nuclear fission processes and energy release calculations.
  • Explore the efficiency of different types of engines, particularly nuclear propulsion.
  • Investigate the implications of drag forces on ship performance and fuel efficiency.
USEFUL FOR

Students and professionals in physics, engineering, and naval architecture, particularly those interested in nuclear propulsion and energy efficiency calculations.

laydico
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I need help finding the solution to this problem...

Suppose that the waterf exerts an average frictional drag of 1.0 X 10^5 N on a nuclear-powered ship. How far can the ship travel per kilogram of fuel if the fuel consists of enriched uranium containing 1.7% of the fissionable isotope 235U and the ship's engine has an efficieny of 20% (assume 208 MeV is released per fission event.)

I know the answer is 2.9 X 10^3 km (1800 miles) I just don't know how to get to it.
 
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One is suppose to show one's work before asking for assistance.

HINT: Thik about the definition of work done.

Regards,
~H
 
i figured it out
 

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