Find solutions in natural numbers

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Discussion Overview

The discussion revolves around finding solutions in natural numbers for a specific mathematical equation involving a series of fractions that sum to 5. The equation includes factorial terms and is presented in a mathematical format.

Discussion Character

  • Mathematical reasoning

Main Points Raised

  • Post 1 presents the equation and asks for solutions in natural numbers.
  • Post 2 reiterates the same equation and request for solutions.
  • Post 3 expresses enthusiasm about the discussion.
  • Post 4 acknowledges the contributions of another participant positively.

Areas of Agreement / Disagreement

The discussion does not appear to have any substantive disagreement or resolution of the mathematical problem, as the main focus is on the equation itself and expressions of support among participants.

Contextual Notes

The equation's complexity and the nature of its solutions in natural numbers are not fully explored, leaving potential assumptions and mathematical steps unresolved.

Who May Find This Useful

Participants interested in mathematical problem-solving, particularly in the context of equations involving factorials and natural numbers.

anemone
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Find the solutions in natural numbers for the following equation:

$$\frac{10}{x+10}+\frac{10\cdot 9}{(x+10)(x+9)}+\cdots+\frac{10\cdot 9\cdot 8 \cdots\cdot 3 \cdot 2 \cdot 1}{(x+10)(x+9)(x+8)\cdots(x+3)(x+2)(x+1)}=5$$
 
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anemone said:
Find the solutions in natural numbers for the following equation:

$$\frac{10}{x+10}+\frac{10\cdot 9}{(x+10)(x+9)}+\cdots+\frac{10\cdot 9\cdot 8 \cdots\cdot 3 \cdot 2 \cdot 1}{(x+10)(x+9)(x+8)\cdots(x+3)(x+2)(x+1)}=5$$

Let $S$ be the sum Let $x=1$. Then we have
$$S=\dfrac{1}{11}\sum_{n=1}^{10}n=5$$ so $x=1$ is a solution. Increasing $x$ will result in a smaller sum (as the denominators of the fractions will be larger), so the only solution is $x=1$.
 
greg1313 said:
Let $S$ be the sum Let $x=1$. Then we have
$$S=\dfrac{1}{11}\sum_{n=1}^{10}n=5$$ so $x=1$ is a solution. Increasing $x$ will result in a smaller sum (as the denominators of the fractions will be larger), so the only solution is $x=1$.
Awesome! (Bow)

-Dan
 
Good job, greg1313!(Cool)
 

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