Find spin only magnetic moment of [Fe(H2O)5NO](2+)

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SUMMARY

The spin-only magnetic moment of the complex [Fe(H2O)5NO]^{2+} is determined to be 3.87, indicating the presence of five unpaired electrons. The iron (Fe) is in the +1 oxidation state with an electron configuration of [Ar]3d^64s^1. However, there is confusion regarding the oxidation states, as some sources indicate Fe in the +3 state and NO in the -1 state, which would also suggest five unpaired electrons. This discrepancy highlights the need for updated information, as older textbooks may contain outdated data.

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  • Understanding of oxidation states in transition metals
  • Knowledge of electron configurations, specifically for iron
  • Familiarity with the concept of magnetic moments in coordination complexes
  • Basic grasp of ligand field theory and its implications on electron pairing
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  • Research the latest literature on the oxidation states of iron complexes
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Chemistry students, particularly those studying coordination chemistry, inorganic chemists, and educators seeking to clarify concepts related to magnetic moments and oxidation states in transition metal complexes.

Titan97
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Homework Statement


Find spin only magnetic moment of ##[Fe(H2O)5NO]^{2+}##

Homework Equations


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The Attempt at a Solution


When I used Google, the magnetic moment in 3.87
##Fe## is in +1 oxidation state. So configuration is $$[Ar]3d^64s^1$$
There are 5 unpaired electrons. How does magnetic moment become 3.87?
 
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the configuration readjusts to 3d7. And there are more problems: Fe is said to be in +3 and NO is in -1. Look it up in Google.
 
If that's the case, then there are 5 unpaired electrons. Magnetic moment won't be 3.87
 
Yeah, I know. And it is a problem for me too, for my textbook says that it is Fe+ and NO+. But apparently that is 15 year old data. I'm not sure which one to follow, and as of now, I have no time to follow my research on the net up. I will look it up again and get back.
 
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