8 grams of Sulfur is burnt in Oxygen to form SO2 which is oxidized by Chlorine water. The solution is treated with BaCl2 solution. The amount of BaSO4 precipitated is ?
SO2 + Cl2 + H2O = SO3 + 2HCl
SO3 + HCl + BaCl2 = BaSO4 + HCl
I do not know if the second one is right and if right, how to balance it?
The Attempt at a Solution
Prima facie it appears that 0.25 mol of S reacts with 0.25 mol of O2 to produce 0.25 mol of SO2.
Beyond this, I do not know how to proceed since the second equation is not balanced.