Gravimetric Analysis- precipitation method

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Discussion Overview

The discussion revolves around a homework problem related to gravimetric analysis using the precipitation method. Participants are tasked with calculating the percentage of chlorine in a hydrated metal chloride and determining the relative atomic mass of the metal involved.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant presents a balanced equation for the reaction involving the hydrated chloride and silver nitrate, expressing uncertainty about its correctness.
  • Another participant suggests calculating the mass of chlorine from the mass of silver chloride (AgCl) to simplify the problem.
  • There is a discussion about the number of moles of chlorine and the molar mass of the hydrated chloride, with one participant attempting to clarify how to calculate these values.
  • Confusion arises regarding the calculation of the percentage of chlorine in the original hydrated chloride versus in AgCl, with participants debating the relationship between these percentages.
  • One participant emphasizes the need to address each compound separately when calculating percentages, indicating a misunderstanding in the approach taken by another participant.
  • Questions are raised about the molar mass of the compound MCl2.2H2O and how to derive it from the given data.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct approach to calculating the percentage of chlorine and the molar mass of the metal. Multiple competing views and methods are presented, indicating that the discussion remains unresolved.

Contextual Notes

Participants express uncertainty regarding the relationships between the masses and percentages of chlorine in different compounds, as well as how to correctly apply the molar mass in their calculations. There are also unresolved questions about the assumptions needed for the calculations.

Who May Find This Useful

Students studying gravimetric analysis, particularly those working on problems involving precipitation methods and the calculation of percentages in chemical compounds.

leah3000
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Homework Statement



1.046g of the hydrated chloride of a certain metal were dissolved in water and silver chloride was precipitated by the addition of a slight excess of silver nitrate solution. After purification the silver chloride had a mass of 1.231g. Calculate the percentage of chlorine in the hydrate. If it is of the form, MCl2.2H2O, calculate the relative atomic mass of the metal, M.


Homework Equations



My attempt at a balanced equation for this:

XCl.xH2O + H2O + AgNO3 ---> AgCl + XNO3

not sure if that's correct

The Attempt at a Solution



no. of mols AgCl produced = Mass/ Mr = 1.231/(108)+(35.5) = 8.58x 10^-3 mols AgCl

From the equation, I assumed a 1:1 ration between AgCl and the hydrated chloride.
Hence, no. of mols hydrated chloride = 8.58x10^-3.

I was trying to calculate the Mr of the hydrated chloride but how do i calculate this if i have 2 variables? The mass of the element X and the no. of mols of water?

I was thinking i'd need to calculate the Mr and then divide the mass of chlorine by the Mr of the compound...then multiply by 100 to find the %:confused:

Can someone please help me!
 
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You are making it harder than it really is. What is mass of chlorine in 1.231g of AgCl? Once you know mass of Cl, calculating its percentage is a breeze.

Now, how many moles of Cl? How many moles of MCl2? Molar mass of MCl2.2H2O? Molar mass of M?

--
methods
 
Borek said:
You are making it harder than it really is. What is mass of chlorine in 1.231g of AgCl? Once you know mass of Cl, calculating its percentage is a breeze.

Now, how many moles of Cl? How many moles of MCl2? Molar mass of MCl2.2H2O? Molar mass of M?

--
chemical calculators - buffer calculator, concentration calculator
www.titrations.info - all about titration methods



ok so to calculate the mass of Cl do i still use the no. of mols as 8.58x10^-3? which could then give a mass of 0.305g?

Also if i use this mass to calculate the percentage of Cl, wouldn't that give me the percentage in AgCl (24.8%)? So then do i just subtract this from 100 to get the percentage in the hydrated halide (75.2%)?

I'm really not sure about this...can u explain the MCl2.2H2O part please.
 
leah3000 said:
ok so to calculate the mass of Cl do i still use the no. of mols as 8.58x10^-3? which could then give a mass of 0.305g?

This is correct mass of chlorine.

Also if i use this mass to calculate the percentage of Cl, wouldn't that give me the percentage in AgCl (24.8%)?

You can as well use this mass to calculate percentage of chloride in the original chloride - you were given the mass, and you can be sure 0.305g is also a mass of chlorides in the original sample. There is no other source of chlorides.

So then do i just subtract this from 100 to get the percentage in the hydrated halide (75.2%)?

No, that's completely off and these numbers are unrelated. When it comes to percentages you need to look at each compound separately.

I'm really not sure about this...can u explain the MCl2.2H2O part please.

Try to answer questions I have already asked (in the order they were asked, using answer to the previous one to find answer to the next). How many moles of Cl? How many moles of MCl2? Molar mass of MCl2.2H2O? Molar mass of M?

--
 

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