1. The problem statement, all variables and given/known data The organic solvent thiophene is a carbon-hydrogen-sulfur compound that makes C02, H20 AND S02 when burned in excess Oxygen. When subject to combustion analysis, a 1.3020g sample makes 2.7244 g CO2, .5575G H20 and .99151 SO2. Find the empirical formula of thiophene 2. Relevant equations None? 3. The attempt at a solution so first i wrote out the combustion Thiophene + O2 <> CO2+ H20+SO2 but i cant balance it yet I then found the amount of moles the compunts on teh right side CO2= 2.772g/44.009g/mol = .06186 moles / .00309 ~ 20 mol H20= .5575g/18.019g/mol= .00309mole / .00309 = 1 mol SO2=.9915g/64.045g/mol = .01548 mole / .00309 ~5 mol therefore Thiophene + O2 <> 20(CO2)+ H20+5(SO2) \ But I have no idea where to go from here, any one have any hints?