Find the amount of Barium Sulphate precipitated

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Discussion Overview

The discussion revolves around a chemistry homework problem involving the combustion of sulfur in oxygen, the subsequent reactions with chlorine water, and the precipitation of barium sulfate (BaSO4) when treated with barium chloride (BaCl2). Participants are attempting to clarify the chemical equations involved and determine the amount of BaSO4 precipitated.

Discussion Character

  • Homework-related
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant questions the validity of the second reaction equation provided, stating it is incorrect.
  • Another participant expresses confusion regarding the role of chlorine water and suggests it may refer to aqueous hydrochloric acid.
  • A participant corrects the first reaction equation to S + O2 = SO2 and notes that 8 grams of sulfur corresponds to 0.25 moles.
  • There is a proposal that the second equation could be adjusted to include water, resulting in SO3 + HCl + BaCl2 + H2O = BaSO4 + 3HCl.
  • One participant concludes that based on the stoichiometry, the amount of BaSO4 precipitated is likely 0.25 moles, but seeks confirmation on the correctness of their reasoning.

Areas of Agreement / Disagreement

Participants express disagreement regarding the correctness of the second reaction equation and the role of chlorine water. There is no consensus on the final equations or the exact amount of BaSO4 precipitated, as some participants propose different interpretations and adjustments.

Contextual Notes

Participants have not fully resolved the balancing of the chemical equations, and there are uncertainties regarding the involvement of water in the reactions. The discussion reflects various interpretations of the problem and the chemical processes involved.

Quantum Mind
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Homework Statement



8 grams of Sulfur is burnt in Oxygen to form SO2 which is oxidized by Chlorine water. The solution is treated with BaCl2 solution. The amount of BaSO4 precipitated is ?

Homework Equations



SO2 + Cl2 + H2O = SO3 + 2HCl

SO3 + HCl + BaCl2 = BaSO4 + HCl

I do not know if the second one is right and if right, how to balance it?

The Attempt at a Solution



Prima facie it appears that 0.25 mol of S reacts with 0.25 mol of O2 to produce 0.25 mol of SO2.

Beyond this, I do not know how to proceed since the second equation is not balanced.
 
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Where did that second reaction equation come from? It's wrong.
 
yea if they are having you make the equations the chlorine water is a little confusing. Do they mean aqueous hydrochloric acid? You also need to use the equation for the burning of sulfur in oxygen (a reaction I do not recommend trying to do).
 
@ zaldar:

The first equation should be S + O2 = SO2.

Since Sulfur is only 8 grams (one-fourth of a mole), the quantities involved in this equation are all 0.25 mole. That is easy to figure out.

The question is correct. The answers are

  1. 1 mole
  2. 0.5 mole
  3. 0.4 mole
  4. 0.25 mole

I know it is only a question of using the law of equivalent proportions, but I am unable to find the right equations.

"The solution is treated with BaCl2 solution"


Perhaps, this means that H2O is also involved ?

In that case, the second equation would be:

SO3 + HCl + BaCl2 + H2O = BaSO4 + 3HCl

Since we originally started off with 0.25 mole of S & O2 and now we have an equivalent proportion of Ba i.e. 0.25 mole, I guess the answer is 0.25 mole. Am I right ?
 
Last edited:
Quantum Mind said:
"The solution is treated with BaCl2 solution"[/I]

Perhaps, this means that H2O is also involved ?

In that case, the second equation would be:

SO3 + HCl + BaCl2 + H2O = BaSO4 + 3HCl
Yup, that looks much better.
 

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