Find the change in mass from the KE (nuclear decay)

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SUMMARY

The discussion centers on calculating the change in mass resulting from nuclear decay, specifically when a nucleus A decays into two nuclei B and C with a combined kinetic energy of 581.9 MeV. The correct difference between the rest mass of nucleus A and the combined rest mass of nuclei B and C is determined to be 0.62319 u, while an initial calculation yielded 0.62469 u. The discrepancy arises from the precision required in using atomic mass units, emphasizing the necessity of maintaining at least five significant digits in calculations.

PREREQUISITES
  • Understanding of nuclear decay processes
  • Familiarity with kinetic energy in nuclear reactions
  • Knowledge of atomic mass units (u) and their conversions
  • Proficiency in applying Einstein's mass-energy equivalence principle (Δmc²)
NEXT STEPS
  • Study the principles of nuclear decay and energy conservation
  • Learn about precision in measurements and calculations in physics
  • Explore the conversion factors between MeV and atomic mass units
  • Investigate common pitfalls in mass-energy calculations in nuclear physics
USEFUL FOR

Students and educators in physics, particularly those focusing on nuclear physics and energy calculations, as well as anyone involved in advanced high school or undergraduate-level physics coursework.

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Homework Statement


A nucleus A decays into two nuclei B and C. The two nuclei have a combined kinetic energy of 581.9 MeV. What is the difference between the rest mass of the parent nucleus A and the combined rest mass of the two produced nuclei? Give your answer in atomic mass units u, with 5 decimals.

Homework Equations


Δmc2 = KEB + KEC
1 u = 931.5 MeV/c^2

The Attempt at a Solution


Δm = KE (Total given in problem statement) / c2 * c2 / 931.5 MeV
Δm = .62469 u

This is incorrect the correct answer is .62319 u

Close but not quite; what am I missing?
 
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You should use the atomic mass unit with at least 5 digits if the answer asks for 5 digits, better 6 or even 7.
.62469 u is much closer to the right answer than .62319 u, however, and I don't see an obvious way how to arrive at the wrong answer. The old chemistry/physics definitions of the atomic unit are too close to explain the difference, and there is no single-digit typo that would lead to the wrong answer.
 

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