Find the current flowing through the 3 ohm resistor.

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SUMMARY

The discussion centers on calculating the current flowing through a 3-ohm resistor in a circuit containing a 6-ohm resistor in parallel with it, followed by a 10-ohm resistor in series. The total resistance of the parallel combination is determined to be 2 ohms, leading to a total circuit resistance of 12 ohms. According to Ohm's Law, the total current in the circuit is calculated to be 1 Ampere. To find the current specifically through the 3-ohm resistor, the voltage drop across the parallel resistor pair must be computed.

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You need to show your attempt at a solution.
Have you computed the total resistance of that resistor network?
What is that -(.)- symbol?
 
The (.) means a closed key= closed circuit. THe current is flowing.
I have done this:
1/R= 1/6+1/3= 3/6= 1/2 (the 6 ohm and 3 ohm resistors are in ||)
R= 2 ohms
Now:
(2+10) ohms= 12 ohms (They are now in series)
Acc. to Ohm's law:
I= V/R
= 12/12
= 1 Ampere
Now I have found the total current in the circuit.
But I need to find the current through the 3 ohm resistor. I can't do it. Please help me find the current through the 3 ohm resistor.
 
You have 1 amp across the 3-ohm/6-ohm pair. You know the resistance of that pair, so you can compute the voltage drop across it.
Then you will know the voltage across the 3-ohm.
 
Current through the 3Ω resistor can be calculated if you know the voltage across it.
Is it possible to determine what this voltage is?
 

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