- #1

calif2a8

- 3

- 0

I thought this would be pretty straight forward but I am completely stumped. So obviously square root is not defined for (-inf, 0), therefore I said:

2x-x^3 >= 0

Working this out you get x <= sqrt(2) as the domain.

That is partially correct but I can't for the life of me get the rest of the answer.

The final answer is (-inf,-sqrt(2)] and [0, sqrt(2)]

HOW do you find out that (-sqrt(2), 0) is not defined?

Thanks for the read and help :D