- #1
calif2a8
- 3
- 0
What is the domain of sqrt(2x-x^3)
I thought this would be pretty straight forward but I am completely stumped. So obviously square root is not defined for (-inf, 0), therefore I said:
2x-x^3 >= 0
Working this out you get x <= sqrt(2) as the domain.
That is partially correct but I can't for the life of me get the rest of the answer.
The final answer is (-inf,-sqrt(2)] and [0, sqrt(2)]
HOW do you find out that (-sqrt(2), 0) is not defined?
Thanks for the read and help :D
I thought this would be pretty straight forward but I am completely stumped. So obviously square root is not defined for (-inf, 0), therefore I said:
2x-x^3 >= 0
Working this out you get x <= sqrt(2) as the domain.
That is partially correct but I can't for the life of me get the rest of the answer.
The final answer is (-inf,-sqrt(2)] and [0, sqrt(2)]
HOW do you find out that (-sqrt(2), 0) is not defined?
Thanks for the read and help :D