Find the equation for velocity as a function of time

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SUMMARY

The discussion focuses on deriving the equation for velocity as a function of time for a rock sliding on a horizontal surface under the influence of a retarding force proportional to the square root of its instantaneous velocity. The force is defined as F = -k * v^(0.5), leading to the acceleration equation a = dv/dt = -k/m * v^(0.5). The solution involves integrating this equation, resulting in the final expression for velocity: v = vi - ((vi)^0.5 * k * t)/m + (k^2 * t^2)/(4m^2), where vi is the initial velocity.

PREREQUISITES
  • Understanding of Newton's second law (F = ma)
  • Knowledge of basic calculus, specifically integration techniques
  • Familiarity with the concept of retarding forces in physics
  • Ability to manipulate algebraic expressions and equations
NEXT STEPS
  • Study integration techniques in calculus, focusing on definite and indefinite integrals
  • Learn about motion under non-constant acceleration
  • Explore the implications of retarding forces in real-world scenarios
  • Investigate the relationship between force, mass, and acceleration in different contexts
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators seeking to explain the concepts of forces and motion under retarding conditions.

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Homework Statement



A rock with mass "m" slides with initial velocity on a horizontal surface. A retarding force F that the surface exerts on the rock is proportional to the square root of the instantaneous velocity of the rock: F = -k * v^(0.5)

Find the equation for velocity as a function of time.

Homework Equations



F = ma
a = dv/dt

The Attempt at a Solution



I'm using online software and used up all my attempts at the answer, so it gave it to me:
vi = initial velocity
v = vi - ((vi)^0.5 * k * t)/m + (k^2 * t^2)/(4m^2)

And I have no idea how to get this. I'm thinking this is because I don't know much about integration. I'm hoping somebody could help me out in explaining this to me, even just a brief outline of the steps to the final answer would be great.

Any help is really appreciated, thanks
 
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[tex]F = -kv^{1/2}[/tex]

[tex]a = \frac{dv}{dt} = -\frac{k}{m}v^{1/2}[/tex]

[tex]\frac{dv}{v^{1/2}} = -\frac{k}{m}dt[/tex]

Taking integration you get

[tex]2v^{1/2} = -\frac{k}{m}t + C[/tex]

When t = 0, [tex]C = 2v_o^{1/2}[/tex]

[tex]2v^{1/2} = -\frac{k}{m}t + 2v_o^{1/2}[/tex]

Square both the sides and simplify.
 

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