nuagerose
- 12
- 0
A box contains four tickets, numbered 0,1,1, and 2. Let Sn be the sum of the numbers obtained from n draws at random with replacement from the box.
Find the exact formula for P(Sn=k) (k=0,1,2...)
I started by finding the probability of the first few sums:
P(Sn=0) = (1/4)^n
P(Sn=1) = n * (1/4)^(n-1) * (1/2)
P(Sn=2) = n * (1/4)^(n-1)*(1/4) + (n choose 2) * (1/4)^(n-2)(1/2)^2
Then I get stuck, since the combinations of draws that lead to the subsequent draws get much more complicated.
Is there a more simplified way to find the formula for P(Sn=k)?
Find the exact formula for P(Sn=k) (k=0,1,2...)
I started by finding the probability of the first few sums:
P(Sn=0) = (1/4)^n
P(Sn=1) = n * (1/4)^(n-1) * (1/2)
P(Sn=2) = n * (1/4)^(n-1)*(1/4) + (n choose 2) * (1/4)^(n-2)(1/2)^2
Then I get stuck, since the combinations of draws that lead to the subsequent draws get much more complicated.
Is there a more simplified way to find the formula for P(Sn=k)?