Find the exact value of tan 285 deg + cos 75 deg + cot 60 deg

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Homework Help Overview

The problem involves finding the exact value of the expression tan 285 degrees + cos 75 degrees + cot 60 degrees, with an emphasis on expressing the result in fractional form rather than decimals.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to convert the angles to radians and expresses concern about the lack of special values for 5pi/12. They question whether they are missing important information regarding the identities needed to solve the problem.
  • Some participants suggest using trigonometric identities, such as the relationship between tangent and cotangent, to explore potential simplifications.
  • Others note that 5pi/12 does not correspond to a special angle in the unit circle, raising questions about how to evaluate the sine and cosine of this angle.

Discussion Status

The discussion is ongoing, with participants exploring various identities and relationships between trigonometric functions. There is acknowledgment of the complexity of evaluating the angles involved, particularly 5pi/12, and some guidance has been offered regarding the use of sine and cosine identities.

Contextual Notes

The original poster indicates a time constraint due to an upcoming test, which may influence the urgency and focus of the discussion. There is also a mention of the requirement for the answer to be in fractional form.

markm
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the question is: find the exact value of tan 285 deg + cos 75 deg + cot 60 deg

i tried converting them to radians and got

tan 5pi / 12 + cos 5 pi / 12 + cot pi / 3

by "exact value", the question means fractions, not decimals. as far as i know, only the cot part has some special identity. am i missing something important? we have a long test tomorrow..

thanks in advance for any help. ^_^
 
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Use the fact that
\tan x=\frac{1}{\cot x}=\frac{\sin x}{\cos x}

Daniel.
 
that still wouldn't help because 5pi/12 has no special values (i.e. sin pi/6 = 1/2, sin pi/3 = sqrt3 / 2, etc.). it's not a special angle in the unit circle.. :(
 
\sin\frac{5\pi}{12}=\sin(\pi-\frac{\pi}{3}-\frac{\pi}{4})=\sin(\frac{2\pi}{3}-\frac{\pi}{4})

which involves "special angles"...

Daniel.
 
thanks a lot. :)
 

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