# Find the force that the magnetic field applies on the wire

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1. Mar 23, 2016

1. The problem statement, all variables and given/known data
Find the force that the magnetic field with B=10^-2 T applies on the wire with length 20 cm when it forms with the force the angle 30 grades when in it passes the intensity 5A.

2. Relevant equations
F=B*I(intensity)*l(length)*sin alpha

3. The attempt at a solution
F=10^-2*5*0.2*0.5=5*10^-3
The solution in my book is 3.5*10^-3N

2. Mar 24, 2016

### drvrm

i think by intensity 5A you mean the current through the wire.
the other angle given "when it forms with the force the angle 30 grades" what grades signifies- see conversion of grades to degree.

3. Mar 24, 2016

yes the current through the wire is 5 A and 30 grades=pi/6 radian

4. Mar 24, 2016

### drvrm

So , one grade =pi/180 radians, then why one uses a different names-give reference

5. Mar 24, 2016

I translated it. but the angle is pi/6 radian

6. Apr 12, 2016

If you understood the problem, could you tell me if I have done it correctly because my solution is different from the one in the book

7. Apr 12, 2016

### drvrm

well i looked for the unit grade as angle measurer
The gradian is a unit of measurement of an angle, equivalent to 1⁄400 of aturn,[1] 9⁄10 of a degree or π⁄200 of a radian.

It is also known as gon (from Greek γωνία/gōnía for angle), grad, or grade. In continental Europe,
see details

so if you use the conversion does the result change?

8. Apr 12, 2016

### drvrm

the underlined statement is also to be clarified- paste a copy of the original problem.

9. Apr 12, 2016

http://tinypic.com/view.php?pic=xcnj0n&s=9#.Vw0EfJx95kg
We use this kind of relationship in physics everyday. I'm sure that the angle is pi/6 radian

10. Apr 12, 2016