Find the force that the magnetic field applies on the wire

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Homework Help Overview

The discussion revolves around calculating the force exerted by a magnetic field on a wire. The magnetic field strength is given as B=10^-2 T, the wire length is 20 cm, the current through the wire is 5 A, and there is an angle of 30 grades (or pi/6 radians) involved in the calculation.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants discuss the formula for calculating the force and the interpretation of the angle measurement in grades versus radians. There are attempts to clarify the meaning of "grades" and its conversion to radians. Some participants question the correctness of the original poster's solution compared to a reference solution in a textbook.

Discussion Status

There is an ongoing exploration of the angle measurement and its implications for the calculation. Participants are actively questioning the assumptions made regarding the angle and the current, and they are seeking clarification on the original problem statement. No consensus has been reached regarding the correctness of the calculations presented.

Contextual Notes

Participants note the potential confusion surrounding the term "grades" as an angle measurement and its equivalence to radians. There is also mention of the original problem statement needing clarification to ensure accurate interpretation.

zade70
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Homework Statement


Find the force that the magnetic field with B=10^-2 T applies on the wire with length 20 cm when it forms with the force the angle 30 grades when in it passes the intensity 5A.

Homework Equations


F=B*I(intensity)*l(length)*sin alpha

The Attempt at a Solution


F=10^-2*5*0.2*0.5=5*10^-3
The solution in my book is 3.5*10^-3N
 
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zade70 said:
Find the force that the magnetic field with B=10^-2 T applies on the wire with length 20 cm when it forms with the force the angle 30 grades when in it passes the intensity 5A.

Homework Equations


i think by intensity 5A you mean the current through the wire.
the other angle given "when it forms with the force the angle 30 grades" what grades signifies- see conversion of grades to degree.
 
drvrm said:
i think by intensity 5A you mean the current through the wire.
the other angle given "when it forms with the force the angle 30 grades" what grades signifies- see conversion of grades to degree.
yes the current through the wire is 5 A and 30 grades=pi/6 radian
 
zade70 said:
yes the current through the wire is 5 A and 30 grades=pi/6 radian

So , one grade =pi/180 radians, then why one uses a different names-give reference
 
drvrm said:
So , one grade =pi/180 radians, then why one uses a different names-give reference
I translated it. but the angle is pi/6 radian
 
drvrm said:
So , one grade =pi/180 radians, then why one uses a different names-give reference
If you understood the problem, could you tell me if I have done it correctly because my solution is different from the one in the book
 
zade70 said:
If you understood the problem, could you tell me if I have done it correctly because my solution is different from the one in the book

well i looked for the unit grade as angle measurer
The gradian is a unit of measurement of an angle, equivalent to 1⁄400 of aturn,[1] 9⁄10 of a degree or π⁄200 of a radian.

It is also known as gon (from Greek γωνία/gōnía for angle), grad, or grade. In continental Europe,
see details
https://en.wikipedia.org/wiki/Gradian

so if you use the conversion does the result change?
 
zade70 said:
Find the force that the magnetic field with B=10^-2 T applies on the wire with length 20 cm when it forms with the force the angle 30 grades when in it passes the intensity 5A.

the underlined statement is also to be clarified- paste a copy of the original problem.
 
http://tinypic.com/view.php?pic=xcnj0n&s=9#.Vw0EfJx95kg
drvrm said:
well i looked for the unit grade as angle measurer
The gradian is a unit of measurement of an angle, equivalent to 1⁄400 of aturn,[1] 9⁄10 of a degree or π⁄200 of a radian.

It is also known as gon (from Greek γωνία/gōnía for angle), grad, or grade. In continental Europe,
see details
https://en.wikipedia.org/wiki/Gradian

so if you use the conversion does the result change?
We use this kind of relationship in physics everyday. I'm sure that the angle is pi/6 radian
 
  • #10
drvrm said:
the underlined statement is also to be clarified- paste a copy of the original problem.
http://postimg.org/image/tk7177rg7/
In this image Intensity is 5 Amper, the angle is pi/6 radian
 

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