Cake
- 100
- 16
Homework Statement
An elevator rises at a constant velocity. A marble is dropped from a hole in the elevator at time T_1. It accelerates downward at 9.8 m/s^2 and hits the floor at time T_2. Define the height at time T_1
Homework Equations
y=y_0+v_0 t-1/2gt^2
The Attempt at a Solution
So this sounds easy as cake. The initial velocity is 0 and we can assume T_1 is 0. Ok, so I can define the function of position as:
y=y_0-4.9t^2 which at time T_2 equals 0.
so
y_0=4.9(T_2)^2
Sound reasonable?
But for some reason the hint in the back of the book is this example of what the answer is supposed to look like. It says:
T_1=T_2=4 then y_0=39.2
Which doesn't line up with my equation that I've used to determine the height. So idk. What did I do wrong?