An elevator rises at a constant velocity. A marble is dropped from a hole in the elevator at time [itex]T_1[/itex]. It accelerates downward at 9.8 m/s^2 and hits the floor at time [itex]T_2[/itex]. Define the height at time [itex]T_1[/itex]
The Attempt at a Solution
So this sounds easy as cake. The initial velocity is 0 and we can assume [itex]T_1[/itex] is 0. Ok, so I can define the function of position as:
[itex]y=y_0-4.9t^2[/itex] which at time [itex]T_2[/itex] equals 0.
But for some reason the hint in the back of the book is this example of what the answer is supposed to look like. It says:
[itex]T_1=T_2=4[/itex] then [itex]y_0=39.2[/itex]
Which doesn't line up with my equation that I've used to determine the height. So idk. What did I do wrong?